[GastForen Programmierung/Entwicklung JavaScript countdown erstellen

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countdown erstellen

juliann
Beiträge gesamt: 8

1. Nov 2004, 13:40
Beitrag # 16 von 17
Beitrag ID: #120332
Bewertung:
(2205 mal gelesen)
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wie soll ich den denn reperieren??

<html>

<head>
<meta name="GENERATOR" content="Microsoft FrontPage 5.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>Countdown zum neuen Jahr 2005</title>
<meta name="Microsoft Border" content="lr, default">
</head>

<HEAD>

<SCRIPT LANGUAGE="JavaScript">

<!-- Begin
//Created by DendE PhisH
function getTime() {
c1 = new Image(); c1.src = "1c.gif";
c2 = new Image(); c2.src = "2c.gif";
c3 = new Image(); c3.src = "3c.gif";
c4 = new Image(); c4.src = "4c.gif";
c5 = new Image(); c5.src = "5c.gif";
c6 = new Image(); c6.src = "6c.gif";
c7 = new Image(); c7.src = "7c.gif";
c8 = new Image(); c8.src = "8c.gif";
c9 = new Image(); c9.src = "9c.gif";
c0 = new Image(); c0.src = "0c.gif";
Cc = new Image(); Cc.src = "Cc.gif";
now = new Date();

//ENTER BELOW THE DATE YOU WISH TO COUNTDOWN TO
later = new Date("Dec 21 2004 15:00:01");

days = (later - now) / 1000 / 60 / 60 / 24;
daysRound = Math.floor(days);
hours = (later - now) / 1000 / 60 / 60 - (24 * daysRound);
hoursRound = Math.floor(hours);
minutes = (later - now) / 1000 /60 - (24 * 60 * daysRound) - (60 * hoursRound);
minutesRound = Math.floor(minutes);
seconds = (later - now) / 1000 - (24 * 60 * 60 * daysRound) - (60 * 60 * hoursRound) - (60 * minutesRound);
secondsRound = Math.round(seconds);

if (secondsRound <= 9) {
document.images.g.src = c0.src;
document.images.h.src = eval("c"+secondsRound+".src");
}
else {
document.images.g.src = eval("c"+Math.floor(secondsRound/10)+".src");
document.images.h.src = eval("c"+(secondsRound%10)+".src");
}
if (minutesRound <= 9) {
document.images.d.src = c0.src;
document.images.e.src = eval("c"+minutesRound+".src");
}
else {
document.images.d.src = eval("c"+Math.floor(minutesRound/10)+".src");
document.images.e.src = eval("c"+(minutesRound%10)+".src");
}
if (hoursRound <= 9) {
document.images.y.src = c0.src;
document.images.z.src = eval("c"+hoursRound+".src");
}
else {
document.images.y.src = eval("c"+Math.floor(hoursRound/10)+".src");
document.images.z.src = eval("c"+(hoursRound%10)+".src");
}
if (daysRound <= 9) {
document.images.x.src = c0.src;
document.images.a.src = c0.src;
document.images.b.src = eval("c"+daysRound+".src");
}
if (daysRound <= 99) {
document.images.x.src = c0.src;
document.images.a.src = eval("c"+Math.floor((daysRound/10)%10)+".src");
document.images.b.src = eval("c"+Math.floor(daysRound%10)+".src");
}
if (daysRound <= 999){
document.images.x.src = eval("c"+Math.floor(daysRound/100)+".src");
document.images.a.src = eval("c"+Math.floor((daysRound/10)%10)+".src");
document.images.b.src = eval("c"+Math.floor(daysRound%10)+".src");
}
newtime = window.setTimeout("getTime();", 1000);
}
// End -->
</script>

</HEAD>


<body>
<BODY onLoad="getTime()">

<p>&nbsp;</p>

<div align="center">
<h3>Countdown zum neuen Jahr 2005</h3>
</div>

<center>
<table><tr><td bgcolor="black" valign="bottom">
<img height=21 src="0c.gif" width=16 name=x>
<img height=21 src="0c.gif" width=16 name=a>
<img height=21 src="0c.gif" width=16 name=b>
<img height=21 src="Cc.gif" width=9 name=c>
<img height=21 src="0c.gif" width=16 name=y>
<img height=21 src="0c.gif" width=16 name=z>
<img height=21 src="Cc.gif" width=9 name=cz>
<img height=21 src="0c.gif" width=16 name=d>
<img height=21 src="0c.gif" width=16 name=e>
<img height=21 src="Cc.gif" width=9 name=f>
<img height=21 src="0c.gif" width=16 name=g>
<img height=21 src="0c.gif" width=16 name=h>
</td></tr></table>
</center>

<div align="center">
<h4>(Tage : Stunden : Minuten : Sekunden)</h4>
</div>

<p><center>
<font face="arial, helvetica" size"-2">Kostenloses JavaScript von<br>
<a href="http://javascriptsource.com">The JavaScript Source</a></font>
</center>

</html>

gruß julian


als Antwort auf: [#118500]
X

countdown erstellen

SabineP
Beiträge gesamt: 7586

1. Nov 2004, 13:54
Beitrag # 17 von 17
Beitrag ID: #120336
Bewertung:
(2205 mal gelesen)
URL zum Beitrag
Beitrag als Lesezeichen
<html>

<head>
<meta name="GENERATOR" content="Microsoft FrontPage 5.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>Countdown zum neuen Jahr 2005</title>
<meta name="Microsoft Border" content="lr, default">

<SCRIPT LANGUAGE="JavaScript">

<!-- Begin
//Created by DendE PhisH
function getTime() {
c1 = new Image(); c1.src = "1c.gif";
c2 = new Image(); c2.src = "2c.gif";
c3 = new Image(); c3.src = "3c.gif";
c4 = new Image(); c4.src = "4c.gif";
c5 = new Image(); c5.src = "5c.gif";
c6 = new Image(); c6.src = "6c.gif";
c7 = new Image(); c7.src = "7c.gif";
c8 = new Image(); c8.src = "8c.gif";
c9 = new Image(); c9.src = "9c.gif";
c0 = new Image(); c0.src = "0c.gif";
Cc = new Image(); Cc.src = "Cc.gif";
now = new Date();

//ENTER BELOW THE DATE YOU WISH TO COUNTDOWN TO
later = new Date("Dec 21 2004 15:00:01");

days = (later - now) / 1000 / 60 / 60 / 24;
daysRound = Math.floor(days);
hours = (later - now) / 1000 / 60 / 60 - (24 * daysRound);
hoursRound = Math.floor(hours);
minutes = (later - now) / 1000 /60 - (24 * 60 * daysRound) - (60 * hoursRound);
minutesRound = Math.floor(minutes);
seconds = (later - now) / 1000 - (24 * 60 * 60 * daysRound) - (60 * 60 * hoursRound) - (60 * minutesRound);
secondsRound = Math.round(seconds);

if (secondsRound <= 9) {
document.images.g.src = c0.src;
document.images.h.src = eval("c"+secondsRound+".src");
}
else {
document.images.g.src = eval("c"+Math.floor(secondsRound/10)+".src");
document.images.h.src = eval("c"+(secondsRound%10)+".src");
}
if (minutesRound <= 9) {
document.images.d.src = c0.src;
document.images.e.src = eval("c"+minutesRound+".src");
}
else {
document.images.d.src = eval("c"+Math.floor(minutesRound/10)+".src");
document.images.e.src = eval("c"+(minutesRound%10)+".src");
}
if (hoursRound <= 9) {
document.images.y.src = c0.src;
document.images.z.src = eval("c"+hoursRound+".src");
}
else {
document.images.y.src = eval("c"+Math.floor(hoursRound/10)+".src");
document.images.z.src = eval("c"+(hoursRound%10)+".src");
}
if (daysRound <= 9) {
document.images.x.src = c0.src;
document.images.a.src = c0.src;
document.images.b.src = eval("c"+daysRound+".src");
}
if (daysRound <= 99) {
document.images.x.src = c0.src;
document.images.a.src = eval("c"+Math.floor((daysRound/10)%10)+".src");
document.images.b.src = eval("c"+Math.floor(daysRound%10)+".src");
}
if (daysRound <= 999){
document.images.x.src = eval("c"+Math.floor(daysRound/100)+".src");
document.images.a.src = eval("c"+Math.floor((daysRound/10)%10)+".src");
document.images.b.src = eval("c"+Math.floor(daysRound%10)+".src");
}
newtime = window.setTimeout("getTime();", 1000);
}
// End -->
</script>

</HEAD>


<BODY onLoad="getTime()">

<p>&nbsp;</p>

<div align="center">
<h3>Countdown zum neuen Jahr 2005</h3>
</div>

<center>
<table><tr><td bgcolor="black" valign="bottom">
<img height=21 src="0c.gif" width=16 name=x>
<img height=21 src="0c.gif" width=16 name=a>
<img height=21 src="0c.gif" width=16 name=b>
<img height=21 src="Cc.gif" width=9 name=c>
<img height=21 src="0c.gif" width=16 name=y>
<img height=21 src="0c.gif" width=16 name=z>
<img height=21 src="Cc.gif" width=9 name=cz>
<img height=21 src="0c.gif" width=16 name=d>
<img height=21 src="0c.gif" width=16 name=e>
<img height=21 src="Cc.gif" width=9 name=f>
<img height=21 src="0c.gif" width=16 name=g>
<img height=21 src="0c.gif" width=16 name=h>
</td></tr></table>
</center>

<div align="center">
<h4>(Tage : Stunden : Minuten : Sekunden)</h4>
</div>

<p><center>
<font face="arial, helvetica" size"-2">Kostenloses JavaScript von<br>
<a href="http://javascriptsource.com">The JavaScript Source</a></font>
</center>
</body>
</html>


als Antwort auf: [#118500]
X